Program to find out the number of days in entered month

//Program to find out the number of days in entered month
#include<stdio.h>
#include<conio.h>
int main()
{
  int m,y;
  clrscr();
  printf("Enter the Month no. and Year\n");
  scanf("%d%d",&m,&y);
  switch(m)
  {
    case 1:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("January has 31 days and Year has 366 days");
    else printf("January has 31 days and Year has 365 days");
    break;

    case 2:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("February has 29 days and Year has 366 days");
    else printf("February has 28 days and Year has 365 days");
    break;

    case 3:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("March has 31 days and Year has 366 days");
    else printf("March has 31 days and Year has 365 days");
    break;

    case 4:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("April has 30 days and Year has 366 days");
    else printf("April has 30 days and Year has 365 days");
    break;

    case 5:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("May has 31 days and Year has 366 days");
    else printf("May has 31 days and Year has 365 days");
    break;

    case 6:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("June has 30 days and Year has 366 days");
    else printf("June has 30 days and Year has 365 days");
    break;

    case 7:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("July has 31 days and Year has 366 days");
    else printf("July has 31 days and Year has 365 days");
    break;

    case 8:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("August has 31 days and Year has 366 days");
    else printf("January has 31 days and Year has 365 days");
    break;

    case 9:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("September has 30 days and Year has 366 days");
    else printf("September has 30 days and Year has 365 days");
    break;

    case 10:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("October has 31 days and Year has 366 days");
    else printf("October has 31 days and Year has 365 days");
    break;

    case 11:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("November has 30 days and Year has 366 days");
    else printf("November has 30 days and Year has 365 days");
    break;

    case 12:
    if(y%4==0&&y%100!=0||y%400==0)
    printf("December has 31 days and Year has 366 days");
    else printf("December has 31 days and Year has 365 days");
    break;

    }
  getch();
  return 0;
}

To Run this Program Copy it in text editor and save as .c
Then double click on it and then it will get opened in your compiler.
Click on run.